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10 answers to this question.

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Most Promoted Answer

19-Apr-2014 22:02:54

pinkyzeal's Answer;must u guys do dis here,i tot it waz a reply to d help i needed only 4 me to open n c dis,,,, itz nt fait

19-Apr-2014 16:23:17

Nawa o, no vex....it was an error!!!bt u sound harsh dooh!!! Abeg

19-Apr-2014 20:51:07

Evaluate 4x^2n+1 - 2^n+1 all over 2^n+1 - 2^n.

Using law of indices,

We av 4x^2n+1 - 2^n+1 all over 2^n+1/n.

Now let's separate them to av

4x^2n+1 over 2^n+1/n - 2^n+1 over 2^n+1/n=0

4x^2n+1 over 2^n+1/n = 2^n+1 over 2^n+1/n.

Now,2^n+1/n will cancel,we're left with 4x^2n+1= 2^n+1 .

Let's take them 2 d simplest form.

(2)^2 (x)^2n+1 = (2)^n+1 (x)^0.

So 2 will cancel and X will cancel to have (2)(2n+1) = (n+1)(0).

4n+2=0,4n=-2.

n = -2/4 = -1/2

Using law of indices,

We av 4x^2n+1 - 2^n+1 all over 2^n+1/n.

Now let's separate them to av

4x^2n+1 over 2^n+1/n - 2^n+1 over 2^n+1/n=0

4x^2n+1 over 2^n+1/n = 2^n+1 over 2^n+1/n.

Now,2^n+1/n will cancel,we're left with 4x^2n+1= 2^n+1 .

Let's take them 2 d simplest form.

(2)^2 (x)^2n+1 = (2)^n+1 (x)^0.

So 2 will cancel and X will cancel to have (2)(2n+1) = (n+1)(0).

4n+2=0,4n=-2.

n = -2/4 = -1/2

19-Apr-2014 21:30:26

Pls what abt me@no 1 material.I had 201 in jamb I am abia state.I want to switch 4rm medisurg to physiotherapy or medical lab which one cuts low. Is advisable. Pls reply me

Other Answers to this question from most recent (10) |

19-Apr-2014 23:05:50

T4 = a + 3d = 13

T10 = a + 9d = 31

a = 13- 3d

13 - 3d + 9d = 31

13+6=31

6d =31-13

6d/6 =18/6

d =3

a=13-3(3)

13-9

a=4

T24 = a + 23d

4 +23(3)

4 +69

T24 = 74

T10 = a + 9d = 31

a = 13- 3d

13 - 3d + 9d = 31

13+6=31

6d =31-13

6d/6 =18/6

d =3

a=13-3(3)

13-9

a=4

T24 = a + 23d

4 +23(3)

4 +69

T24 = 74

19-Apr-2014 16:23:17

Nawa o, no vex....it was an error!!!bt u sound harsh dooh!!! Abeg

19-Apr-2014 19:54:49

Please,how about political science cut off mark?

19-Apr-2014 20:51:07

Evaluate 4x^2n+1 - 2^n+1 all over 2^n+1 - 2^n.

Using law of indices,

We av 4x^2n+1 - 2^n+1 all over 2^n+1/n.

Now let's separate them to av

4x^2n+1 over 2^n+1/n - 2^n+1 over 2^n+1/n=0

4x^2n+1 over 2^n+1/n = 2^n+1 over 2^n+1/n.

Now,2^n+1/n will cancel,we're left with 4x^2n+1= 2^n+1 .

Let's take them 2 d simplest form.

(2)^2 (x)^2n+1 = (2)^n+1 (x)^0.

So 2 will cancel and X will cancel to have (2)(2n+1) = (n+1)(0).

4n+2=0,4n=-2.

n = -2/4 = -1/2

Using law of indices,

We av 4x^2n+1 - 2^n+1 all over 2^n+1/n.

Now let's separate them to av

4x^2n+1 over 2^n+1/n - 2^n+1 over 2^n+1/n=0

4x^2n+1 over 2^n+1/n = 2^n+1 over 2^n+1/n.

Now,2^n+1/n will cancel,we're left with 4x^2n+1= 2^n+1 .

Let's take them 2 d simplest form.

(2)^2 (x)^2n+1 = (2)^n+1 (x)^0.

So 2 will cancel and X will cancel to have (2)(2n+1) = (n+1)(0).

4n+2=0,4n=-2.

n = -2/4 = -1/2

19-Apr-2014 21:30:26

Pls what abt me@no 1 material.I had 201 in jamb I am abia state.I want to switch 4rm medisurg to physiotherapy or medical lab which one cuts low. Is advisable. Pls reply me

19-Apr-2014 23:01:16

Failure

19-Apr-2014 16:23:17

Nawa o, no vex....it was an error!!!bt u sound harsh dooh!!! Abeg

19-Apr-2014 20:51:07

Evaluate 4x^2n+1 - 2^n+1 all over 2^n+1 - 2^n.

Using law of indices,

We av 4x^2n+1 - 2^n+1 all over 2^n+1/n.

Now let's separate them to av

4x^2n+1 over 2^n+1/n - 2^n+1 over 2^n+1/n=0

4x^2n+1 over 2^n+1/n = 2^n+1 over 2^n+1/n.

Now,2^n+1/n will cancel,we're left with 4x^2n+1= 2^n+1 .

Let's take them 2 d simplest form.

(2)^2 (x)^2n+1 = (2)^n+1 (x)^0.

So 2 will cancel and X will cancel to have (2)(2n+1) = (n+1)(0).

4n+2=0,4n=-2.

n = -2/4 = -1/2

Using law of indices,

We av 4x^2n+1 - 2^n+1 all over 2^n+1/n.

Now let's separate them to av

4x^2n+1 over 2^n+1/n - 2^n+1 over 2^n+1/n=0

4x^2n+1 over 2^n+1/n = 2^n+1 over 2^n+1/n.

Now,2^n+1/n will cancel,we're left with 4x^2n+1= 2^n+1 .

Let's take them 2 d simplest form.

(2)^2 (x)^2n+1 = (2)^n+1 (x)^0.

So 2 will cancel and X will cancel to have (2)(2n+1) = (n+1)(0).

4n+2=0,4n=-2.

n = -2/4 = -1/2

19-Apr-2014 21:30:26

Pls what abt me@no 1 material.I had 201 in jamb I am abia state.I want to switch 4rm medisurg to physiotherapy or medical lab which one cuts low. Is advisable. Pls reply me

19-Apr-2014 22:44:59

haemophillia

19-Apr-2014 16:23:17

Nawa o, no vex....it was an error!!!bt u sound harsh dooh!!! Abeg

19-Apr-2014 20:51:07

Using law of indices,

We av 4x^2n+1 - 2^n+1 all over 2^n+1/n.

Now let's separate them to av

4x^2n+1 over 2^n+1/n - 2^n+1 over 2^n+1/n=0

4x^2n+1 over 2^n+1/n = 2^n+1 over 2^n+1/n.

Now,2^n+1/n will cancel,we're left with 4x^2n+1= 2^n+1 .

Let's take them 2 d simplest form.

(2)^2 (x)^2n+1 = (2)^n+1 (x)^0.

So 2 will cancel and X will cancel to have (2)(2n+1) = (n+1)(0).

4n+2=0,4n=-2.

n = -2/4 = -1/2

19-Apr-2014 21:30:26

19-Apr-2014 22:44:11

kilowatt-hour ( kWh)

19-Apr-2014 16:23:17

Nawa o, no vex....it was an error!!!bt u sound harsh dooh!!! Abeg

19-Apr-2014 19:54:49

Please,how about political science cut off mark?

19-Apr-2014 20:51:07

Using law of indices,

We av 4x^2n+1 - 2^n+1 all over 2^n+1/n.

Now let's separate them to av

4x^2n+1 over 2^n+1/n - 2^n+1 over 2^n+1/n=0

4x^2n+1 over 2^n+1/n = 2^n+1 over 2^n+1/n.

Now,2^n+1/n will cancel,we're left with 4x^2n+1= 2^n+1 .

Let's take them 2 d simplest form.

(2)^2 (x)^2n+1 = (2)^n+1 (x)^0.

So 2 will cancel and X will cancel to have (2)(2n+1) = (n+1)(0).

4n+2=0,4n=-2.

n = -2/4 = -1/2

19-Apr-2014 21:30:26

19-Apr-2014 22:41:21

Transitional and Rotational motion

19-Apr-2014 16:23:17

Nawa o, no vex....it was an error!!!bt u sound harsh dooh!!! Abeg

19-Apr-2014 19:54:49

Please,how about political science cut off mark?

19-Apr-2014 20:51:07

Using law of indices,

We av 4x^2n+1 - 2^n+1 all over 2^n+1/n.

Now let's separate them to av

4x^2n+1 over 2^n+1/n - 2^n+1 over 2^n+1/n=0

4x^2n+1 over 2^n+1/n = 2^n+1 over 2^n+1/n.

Now,2^n+1/n will cancel,we're left with 4x^2n+1= 2^n+1 .

Let's take them 2 d simplest form.

(2)^2 (x)^2n+1 = (2)^n+1 (x)^0.

So 2 will cancel and X will cancel to have (2)(2n+1) = (n+1)(0).

4n+2=0,4n=-2.

n = -2/4 = -1/2

19-Apr-2014 21:30:26

19-Apr-2014 22:31:29

A body will continue in its present state of rest, or if it is in motion,will continue to move with uniform speed in a straight line unless it is acted upon by a force.

19-Apr-2014 16:23:17

Nawa o, no vex....it was an error!!!bt u sound harsh dooh!!! Abeg

19-Apr-2014 19:54:49

Please,how about political science cut off mark?

19-Apr-2014 20:51:07

Using law of indices,

We av 4x^2n+1 - 2^n+1 all over 2^n+1/n.

Now let's separate them to av

4x^2n+1 over 2^n+1/n - 2^n+1 over 2^n+1/n=0

4x^2n+1 over 2^n+1/n = 2^n+1 over 2^n+1/n.

Now,2^n+1/n will cancel,we're left with 4x^2n+1= 2^n+1 .

Let's take them 2 d simplest form.

(2)^2 (x)^2n+1 = (2)^n+1 (x)^0.

So 2 will cancel and X will cancel to have (2)(2n+1) = (n+1)(0).

4n+2=0,4n=-2.

n = -2/4 = -1/2

19-Apr-2014 21:30:26

19-Apr-2014 22:15:06

Dear Chigbundu Ogechi Telma

English 31, Govt 38, Maths 31, Econs 30, AGGREGATE 130

English 31, Govt 38, Maths 31, Econs 30, AGGREGATE 130

19-Apr-2014 16:23:17

Nawa o, no vex....it was an error!!!bt u sound harsh dooh!!! Abeg

19-Apr-2014 19:54:49

Please,how about political science cut off mark?

19-Apr-2014 20:51:07

Using law of indices,

We av 4x^2n+1 - 2^n+1 all over 2^n+1/n.

Now let's separate them to av

4x^2n+1 over 2^n+1/n - 2^n+1 over 2^n+1/n=0

4x^2n+1 over 2^n+1/n = 2^n+1 over 2^n+1/n.

Now,2^n+1/n will cancel,we're left with 4x^2n+1= 2^n+1 .

Let's take them 2 d simplest form.

(2)^2 (x)^2n+1 = (2)^n+1 (x)^0.

So 2 will cancel and X will cancel to have (2)(2n+1) = (n+1)(0).

4n+2=0,4n=-2.

n = -2/4 = -1/2

19-Apr-2014 21:30:26

19-Apr-2014 22:08:56

translation and rotational motion

19-Apr-2014 16:23:17

Nawa o, no vex....it was an error!!!bt u sound harsh dooh!!! Abeg

19-Apr-2014 20:51:07

Using law of indices,

We av 4x^2n+1 - 2^n+1 all over 2^n+1/n.

Now let's separate them to av

4x^2n+1 over 2^n+1/n - 2^n+1 over 2^n+1/n=0

4x^2n+1 over 2^n+1/n = 2^n+1 over 2^n+1/n.

Now,2^n+1/n will cancel,we're left with 4x^2n+1= 2^n+1 .

Let's take them 2 d simplest form.

(2)^2 (x)^2n+1 = (2)^n+1 (x)^0.

So 2 will cancel and X will cancel to have (2)(2n+1) = (n+1)(0).

4n+2=0,4n=-2.

n = -2/4 = -1/2

19-Apr-2014 21:30:26

19-Apr-2014 22:02:54

must u guys do dis here,i tot it waz a reply to d help i needed only 4 me to open n c dis,,,, itz nt fait

19-Apr-2014 16:23:17

Nawa o, no vex....it was an error!!!bt u sound harsh dooh!!! Abeg

19-Apr-2014 19:54:49

Please,how about political science cut off mark?

19-Apr-2014 20:51:07

Using law of indices,

We av 4x^2n+1 - 2^n+1 all over 2^n+1/n.

Now let's separate them to av

4x^2n+1 over 2^n+1/n - 2^n+1 over 2^n+1/n=0

4x^2n+1 over 2^n+1/n = 2^n+1 over 2^n+1/n.

Now,2^n+1/n will cancel,we're left with 4x^2n+1= 2^n+1 .

Let's take them 2 d simplest form.

(2)^2 (x)^2n+1 = (2)^n+1 (x)^0.

So 2 will cancel and X will cancel to have (2)(2n+1) = (n+1)(0).

4n+2=0,4n=-2.

n = -2/4 = -1/2

19-Apr-2014 21:30:26

19-Apr-2014 21:52:34

Is enough but aptitude test is d basic. Without it no way

19-Apr-2014 16:23:17

Nawa o, no vex....it was an error!!!bt u sound harsh dooh!!! Abeg

19-Apr-2014 19:54:49

Please,how about political science cut off mark?

19-Apr-2014 20:51:07

Using law of indices,

We av 4x^2n+1 - 2^n+1 all over 2^n+1/n.

Now let's separate them to av

4x^2n+1 over 2^n+1/n - 2^n+1 over 2^n+1/n=0

4x^2n+1 over 2^n+1/n = 2^n+1 over 2^n+1/n.

Now,2^n+1/n will cancel,we're left with 4x^2n+1= 2^n+1 .

Let's take them 2 d simplest form.

(2)^2 (x)^2n+1 = (2)^n+1 (x)^0.

So 2 will cancel and X will cancel to have (2)(2n+1) = (n+1)(0).

4n+2=0,4n=-2.

n = -2/4 = -1/2

19-Apr-2014 21:30:26

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