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# LAUTECH: what are the available part time courses at Lautech?

Posted: 30-May-2013 [22:17:10] by davosfemi

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Name
19-Apr-2014 22:02:54

must u guys do dis here,i tot it waz a reply to d help i needed only 4 me to open n c dis,,,, itz nt fait
19-Apr-2014 16:23:17
Nawa o, no vex....it was an error!!!bt u sound harsh dooh!!! Abeg
19-Apr-2014 19:54:49
19-Apr-2014 20:51:07
Evaluate 4x^2n+1 - 2^n+1 all over 2^n+1 - 2^n.
Using law of indices,
We av 4x^2n+1 - 2^n+1 all over 2^n+1/n.
Now let's separate them to av
4x^2n+1 over 2^n+1/n - 2^n+1 over 2^n+1/n=0
4x^2n+1 over 2^n+1/n = 2^n+1 over 2^n+1/n.
Now,2^n+1/n will cancel,we're left with 4x^2n+1= 2^n+1 .
Let's take them 2 d simplest form.
(2)^2 (x)^2n+1 = (2)^n+1 (x)^0.
So 2 will cancel and X will cancel to have (2)(2n+1) = (n+1)(0).
4n+2=0,4n=-2.
n = -2/4 = -1/2
19-Apr-2014 21:30:26
Pls what abt me@no 1 material.I had 201 in jamb I am abia state.I want to switch 4rm medisurg to physiotherapy or medical lab which one cuts low. Is advisable. Pls reply me
 Other Answers to this question from most recent (10)

19-Apr-2014 23:05:50
T4 = a + 3d = 13
T10 = a + 9d = 31

a = 13- 3d
13 - 3d + 9d = 31
13+6=31
6d =31-13
6d/6 =18/6
d =3
a=13-3(3)
13-9
a=4
T24 = a + 23d
4 +23(3)
4 +69
T24 = 74

19-Apr-2014 16:23:17
Nawa o, no vex....it was an error!!!bt u sound harsh dooh!!! Abeg
19-Apr-2014 19:54:49
19-Apr-2014 20:51:07
Evaluate 4x^2n+1 - 2^n+1 all over 2^n+1 - 2^n.
Using law of indices,
We av 4x^2n+1 - 2^n+1 all over 2^n+1/n.
Now let's separate them to av
4x^2n+1 over 2^n+1/n - 2^n+1 over 2^n+1/n=0
4x^2n+1 over 2^n+1/n = 2^n+1 over 2^n+1/n.
Now,2^n+1/n will cancel,we're left with 4x^2n+1= 2^n+1 .
Let's take them 2 d simplest form.
(2)^2 (x)^2n+1 = (2)^n+1 (x)^0.
So 2 will cancel and X will cancel to have (2)(2n+1) = (n+1)(0).
4n+2=0,4n=-2.
n = -2/4 = -1/2
19-Apr-2014 21:30:26
Pls what abt me@no 1 material.I had 201 in jamb I am abia state.I want to switch 4rm medisurg to physiotherapy or medical lab which one cuts low. Is advisable. Pls reply me

19-Apr-2014 23:01:16
Failure

19-Apr-2014 16:23:17
Nawa o, no vex....it was an error!!!bt u sound harsh dooh!!! Abeg
19-Apr-2014 19:54:49
19-Apr-2014 20:51:07
Evaluate 4x^2n+1 - 2^n+1 all over 2^n+1 - 2^n.
Using law of indices,
We av 4x^2n+1 - 2^n+1 all over 2^n+1/n.
Now let's separate them to av
4x^2n+1 over 2^n+1/n - 2^n+1 over 2^n+1/n=0
4x^2n+1 over 2^n+1/n = 2^n+1 over 2^n+1/n.
Now,2^n+1/n will cancel,we're left with 4x^2n+1= 2^n+1 .
Let's take them 2 d simplest form.
(2)^2 (x)^2n+1 = (2)^n+1 (x)^0.
So 2 will cancel and X will cancel to have (2)(2n+1) = (n+1)(0).
4n+2=0,4n=-2.
n = -2/4 = -1/2
19-Apr-2014 21:30:26
Pls what abt me@no 1 material.I had 201 in jamb I am abia state.I want to switch 4rm medisurg to physiotherapy or medical lab which one cuts low. Is advisable. Pls reply me

19-Apr-2014 22:44:59
haemophillia

19-Apr-2014 16:23:17
Nawa o, no vex....it was an error!!!bt u sound harsh dooh!!! Abeg
19-Apr-2014 19:54:49
19-Apr-2014 20:51:07
Evaluate 4x^2n+1 - 2^n+1 all over 2^n+1 - 2^n.
Using law of indices,
We av 4x^2n+1 - 2^n+1 all over 2^n+1/n.
Now let's separate them to av
4x^2n+1 over 2^n+1/n - 2^n+1 over 2^n+1/n=0
4x^2n+1 over 2^n+1/n = 2^n+1 over 2^n+1/n.
Now,2^n+1/n will cancel,we're left with 4x^2n+1= 2^n+1 .
Let's take them 2 d simplest form.
(2)^2 (x)^2n+1 = (2)^n+1 (x)^0.
So 2 will cancel and X will cancel to have (2)(2n+1) = (n+1)(0).
4n+2=0,4n=-2.
n = -2/4 = -1/2
19-Apr-2014 21:30:26
Pls what abt me@no 1 material.I had 201 in jamb I am abia state.I want to switch 4rm medisurg to physiotherapy or medical lab which one cuts low. Is advisable. Pls reply me

19-Apr-2014 22:44:11
kilowatt-hour ( kWh)

19-Apr-2014 16:23:17
Nawa o, no vex....it was an error!!!bt u sound harsh dooh!!! Abeg
19-Apr-2014 19:54:49
19-Apr-2014 20:51:07
Evaluate 4x^2n+1 - 2^n+1 all over 2^n+1 - 2^n.
Using law of indices,
We av 4x^2n+1 - 2^n+1 all over 2^n+1/n.
Now let's separate them to av
4x^2n+1 over 2^n+1/n - 2^n+1 over 2^n+1/n=0
4x^2n+1 over 2^n+1/n = 2^n+1 over 2^n+1/n.
Now,2^n+1/n will cancel,we're left with 4x^2n+1= 2^n+1 .
Let's take them 2 d simplest form.
(2)^2 (x)^2n+1 = (2)^n+1 (x)^0.
So 2 will cancel and X will cancel to have (2)(2n+1) = (n+1)(0).
4n+2=0,4n=-2.
n = -2/4 = -1/2
19-Apr-2014 21:30:26
Pls what abt me@no 1 material.I had 201 in jamb I am abia state.I want to switch 4rm medisurg to physiotherapy or medical lab which one cuts low. Is advisable. Pls reply me

19-Apr-2014 22:41:21
Transitional and Rotational motion

19-Apr-2014 16:23:17
Nawa o, no vex....it was an error!!!bt u sound harsh dooh!!! Abeg
19-Apr-2014 19:54:49
19-Apr-2014 20:51:07
Evaluate 4x^2n+1 - 2^n+1 all over 2^n+1 - 2^n.
Using law of indices,
We av 4x^2n+1 - 2^n+1 all over 2^n+1/n.
Now let's separate them to av
4x^2n+1 over 2^n+1/n - 2^n+1 over 2^n+1/n=0
4x^2n+1 over 2^n+1/n = 2^n+1 over 2^n+1/n.
Now,2^n+1/n will cancel,we're left with 4x^2n+1= 2^n+1 .
Let's take them 2 d simplest form.
(2)^2 (x)^2n+1 = (2)^n+1 (x)^0.
So 2 will cancel and X will cancel to have (2)(2n+1) = (n+1)(0).
4n+2=0,4n=-2.
n = -2/4 = -1/2
19-Apr-2014 21:30:26
Pls what abt me@no 1 material.I had 201 in jamb I am abia state.I want to switch 4rm medisurg to physiotherapy or medical lab which one cuts low. Is advisable. Pls reply me

19-Apr-2014 22:31:29
A body will continue in its present state of rest, or if it is in motion,will continue to move with uniform speed in a straight line unless it is acted upon by a force.

19-Apr-2014 16:23:17
Nawa o, no vex....it was an error!!!bt u sound harsh dooh!!! Abeg
19-Apr-2014 19:54:49
19-Apr-2014 20:51:07
Evaluate 4x^2n+1 - 2^n+1 all over 2^n+1 - 2^n.
Using law of indices,
We av 4x^2n+1 - 2^n+1 all over 2^n+1/n.
Now let's separate them to av
4x^2n+1 over 2^n+1/n - 2^n+1 over 2^n+1/n=0
4x^2n+1 over 2^n+1/n = 2^n+1 over 2^n+1/n.
Now,2^n+1/n will cancel,we're left with 4x^2n+1= 2^n+1 .
Let's take them 2 d simplest form.
(2)^2 (x)^2n+1 = (2)^n+1 (x)^0.
So 2 will cancel and X will cancel to have (2)(2n+1) = (n+1)(0).
4n+2=0,4n=-2.
n = -2/4 = -1/2
19-Apr-2014 21:30:26
Pls what abt me@no 1 material.I had 201 in jamb I am abia state.I want to switch 4rm medisurg to physiotherapy or medical lab which one cuts low. Is advisable. Pls reply me

19-Apr-2014 22:15:06
Dear Chigbundu Ogechi Telma
English 31, Govt 38, Maths 31, Econs 30, AGGREGATE 130

19-Apr-2014 16:23:17
Nawa o, no vex....it was an error!!!bt u sound harsh dooh!!! Abeg
19-Apr-2014 19:54:49
19-Apr-2014 20:51:07
Evaluate 4x^2n+1 - 2^n+1 all over 2^n+1 - 2^n.
Using law of indices,
We av 4x^2n+1 - 2^n+1 all over 2^n+1/n.
Now let's separate them to av
4x^2n+1 over 2^n+1/n - 2^n+1 over 2^n+1/n=0
4x^2n+1 over 2^n+1/n = 2^n+1 over 2^n+1/n.
Now,2^n+1/n will cancel,we're left with 4x^2n+1= 2^n+1 .
Let's take them 2 d simplest form.
(2)^2 (x)^2n+1 = (2)^n+1 (x)^0.
So 2 will cancel and X will cancel to have (2)(2n+1) = (n+1)(0).
4n+2=0,4n=-2.
n = -2/4 = -1/2
19-Apr-2014 21:30:26
Pls what abt me@no 1 material.I had 201 in jamb I am abia state.I want to switch 4rm medisurg to physiotherapy or medical lab which one cuts low. Is advisable. Pls reply me

19-Apr-2014 22:08:56
translation and rotational motion

19-Apr-2014 16:23:17
Nawa o, no vex....it was an error!!!bt u sound harsh dooh!!! Abeg
19-Apr-2014 19:54:49
19-Apr-2014 20:51:07
Evaluate 4x^2n+1 - 2^n+1 all over 2^n+1 - 2^n.
Using law of indices,
We av 4x^2n+1 - 2^n+1 all over 2^n+1/n.
Now let's separate them to av
4x^2n+1 over 2^n+1/n - 2^n+1 over 2^n+1/n=0
4x^2n+1 over 2^n+1/n = 2^n+1 over 2^n+1/n.
Now,2^n+1/n will cancel,we're left with 4x^2n+1= 2^n+1 .
Let's take them 2 d simplest form.
(2)^2 (x)^2n+1 = (2)^n+1 (x)^0.
So 2 will cancel and X will cancel to have (2)(2n+1) = (n+1)(0).
4n+2=0,4n=-2.
n = -2/4 = -1/2
19-Apr-2014 21:30:26
Pls what abt me@no 1 material.I had 201 in jamb I am abia state.I want to switch 4rm medisurg to physiotherapy or medical lab which one cuts low. Is advisable. Pls reply me

19-Apr-2014 22:02:54
must u guys do dis here,i tot it waz a reply to d help i needed only 4 me to open n c dis,,,, itz nt fait

19-Apr-2014 16:23:17
Nawa o, no vex....it was an error!!!bt u sound harsh dooh!!! Abeg
19-Apr-2014 19:54:49
19-Apr-2014 20:51:07
Evaluate 4x^2n+1 - 2^n+1 all over 2^n+1 - 2^n.
Using law of indices,
We av 4x^2n+1 - 2^n+1 all over 2^n+1/n.
Now let's separate them to av
4x^2n+1 over 2^n+1/n - 2^n+1 over 2^n+1/n=0
4x^2n+1 over 2^n+1/n = 2^n+1 over 2^n+1/n.
Now,2^n+1/n will cancel,we're left with 4x^2n+1= 2^n+1 .
Let's take them 2 d simplest form.
(2)^2 (x)^2n+1 = (2)^n+1 (x)^0.
So 2 will cancel and X will cancel to have (2)(2n+1) = (n+1)(0).
4n+2=0,4n=-2.
n = -2/4 = -1/2
19-Apr-2014 21:30:26
Pls what abt me@no 1 material.I had 201 in jamb I am abia state.I want to switch 4rm medisurg to physiotherapy or medical lab which one cuts low. Is advisable. Pls reply me

19-Apr-2014 21:52:34
Is enough but aptitude test is d basic. Without it no way

19-Apr-2014 16:23:17
Nawa o, no vex....it was an error!!!bt u sound harsh dooh!!! Abeg
19-Apr-2014 19:54:49
19-Apr-2014 20:51:07
Evaluate 4x^2n+1 - 2^n+1 all over 2^n+1 - 2^n.
Using law of indices,
We av 4x^2n+1 - 2^n+1 all over 2^n+1/n.
Now let's separate them to av
4x^2n+1 over 2^n+1/n - 2^n+1 over 2^n+1/n=0
4x^2n+1 over 2^n+1/n = 2^n+1 over 2^n+1/n.
Now,2^n+1/n will cancel,we're left with 4x^2n+1= 2^n+1 .
Let's take them 2 d simplest form.
(2)^2 (x)^2n+1 = (2)^n+1 (x)^0.
So 2 will cancel and X will cancel to have (2)(2n+1) = (n+1)(0).
4n+2=0,4n=-2.
n = -2/4 = -1/2
19-Apr-2014 21:30:26
Pls what abt me@no 1 material.I had 201 in jamb I am abia state.I want to switch 4rm medisurg to physiotherapy or medical lab which one cuts low. Is advisable. Pls reply me

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